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| Problème de N en somme minimale  avec  1, 2, 3, 4 … Obtenir un nombre N en utilisant le minimum de chiffres
  dans l'ordre et les opérations usuelles. Un défi consiste à traduire l'année
  en cours avec ces contraintes. Exemple en utilisant 6! = 720 et 3!4 = 1
  296, faisant un total de 2016. 
 | 
Voir Factorielles
/ Table – Boite à outils des
factorielles
Nombre de 1 à  …
L'astérisque
indique que le chiffre est déjà utilisé.
| N | 1 | 2 | 3 | 4 | 
| 1 | 1 |  |  |  | 
| 2 | 1 | × 2 |  | |
| 3 | 1 | + 2 |  | |
| 4 | –1 | + 2 | + 3 | |
| 5 | 1 | × (2 | + 3) | |
| 6 | 1 | + (2 | + 3) | |
| 7 | –1 | + 2 | + 3! | |
| 8 | 1 | × (2 | + 3!) | |
| 9 | 1 | + 23 | * | |
| 9 | (1 | + 2) | × 3 | |
| 9 | 12 | * | – 3 | |
| 10 | 1 | + 2 | + 3 | + 4 | 
| 11 | 1 | + 2 | × 3 | + 4 | 
| 12 | 12 | * |  | |
| 13 | 12 | * | – 3 | + 4 | 
| 14 | 1 | × (2 | + 3 | × 4) | 
| 15 | 12 |  | + 3 | |
| 16 | 1 | × (2 | +3! ) | 
 | 
| 17 | 1 | + (2 | +3! ) | 
 | 
| 18 | 12 | * | +  3! | |
| 19 | –1 | + (2 | + 3) | × 4 | 
| 20 | 1 | × (2 | + 3) | × 4 | 
| 20 | 1 | × 2 | – 3! | + 4! | 
| 21 | 1 | × 23 | * | 
 | 
| 22 | –1 | + 23 | * | |
| 23 | 1 | × 23 | * | |
| 24 | 1 | + 23 | * | |
| 24 | (12 | * | ÷ 3) ! | 
| N | 1 | 2 | 3 | 4 | 5 | 
| 25 | (1 | + 2)3 | * | 
 |  | 
| 26 | –1 | + 23 | * | + 4 |  | 
| 27 | 1 | × 23 | * | + 4 |  | 
| 28 | 1 | + 23 | * | + 4 |  | 
| 29 | (1 | + 2)3 | * | 
 |  | 
| 30 | (12 | * | + 3) | 
 |  | 
| 30 | (1 | + 2) ! | + 3! | × 4 |  | 
| 30 | (1 | + 2 | + 3) ! | ÷ 4! |  | 
| 31 | (1 | + 2)3 | * | + 4 |  | 
| 31 | 1 | + (2 | × 3) ! | ÷ 4! |  | 
| 32 | 12 | * | × 3 | – 4 |  | 
| 33 | 1 | + 2 | + (3!) ! | ÷ 4! |  | 
| 34 | 12 | * | × 3 | 
 |  | 
| 35 | (–1 | + 2 | + 3 | 
 | × 5 | 
| 36 | 12 | * | × 3 |  | |
| 37 | 1 | × 2 | + (3 | + 4) | × 5 | 
| 38 | 1 | + 2 | + (3 | + 4) | × 5 | 
| 38 | 12 | * | × 3 | 
 |  | 
| 39 | (–1 | + 2 | + 3 | + 4) | × 5 | 
| 40 | 12 | * | × 3 | + 4 |  | 
| 41 | 1 | – 2 | – 3 | + 45 | * | 
| 42 | (1 | – 2) | × 3 | + 45 | * | 
| 43 | –1 | + 2 | – 3 | + 45 | * | 
| 44 | –1 | × (2 | + 3 | + 4) | × 5 | 
| 45 | 1 | × (2 | + 3 | + 4) | × 5 | 
| 46 | 1 | × (– 2 | + 3) | + 45 | * | 
| 47 | 1 | – 2 | + 3 | + 45 | * | 
| 48 | (12 | * | ÷ 3) ! | + 4! |  | 
| 49 | –1 | + 2 | + 3 | + 45 | * | 
| 50 | 1 | × ( 2 | + 3) | + 45 | * | 
| 51 | 1 | + 2 | + 3 | + 45 | * | 
| N | 1 | 2 | 3 | 4 | 5 | 6 | 
|  |  |  |  | |||
| 2008 | –1 | +  (– 2 | + 3!4 | / | – 5 | + 6! ) | 
| 2009 | 1 | × (– 2 | + 3!4 | / | – 5 | + 6! ) | 
| 2010 | 1 | +  (– 2 | + 3!4 | / | – 5 | + 6! ) | 
| 2012 | –1 | + 2 | + 3!4 | / | – 5 | + 6! | 
| 2013 | 1 | ×  (2 | + 3!4 | / | – 5 | + 6! ) | 
| 2014 | 1 | + 2 | + 3!4 | / | – 5 | + 6! | 
| 2015 | 1 | – 2 | + 3!4 | / | + 5! | × 6 | 
|  | 3!4 |  | + 6! | |||
| 2016 |  | 3!4 | + 5!  | × 6 | ||
| 2016 | ((1 | + 2)!
  )! | + 3!4 |  |  | |
| 2017 | –1 | + 2 | + 3!4 | / | + 5! | × 6 | 
| 2018 |  –1 | – 2 | + 3!4 | / | + 5 | + 6! | 
| 2018 | 1 | × 2 | + 3!4 | / | + 5! | × 6 | 
| 2019 | 1 | + 2 | + 3!4 | / | + 5! | × 6 | 
| 2020 | 1 | – 2 | + 3!4 | / | + 5 | + 6! | 
| 2021 | ((1 | + 2)!
  )! | + 3!4 | / | + 5 |  | 
| 2022 |  –1 | + 2 | + 3!4 | / | + 5 | + 6! | 
| 2023 | 1 | × 2 | + 3!4 | / | + 5 | + 6!  | 
| 2024 |  |  |  |  | ||
| 2025 |  |  |  |  | ||
| 2026 |  |  |  |  | ||
| 2027 | ((1 | + 2)! )! | + 3!4 | / | + 5 | + 6 | 
|  |  |  |  |  | 
Voir Brève de
Math 493
Florilège
| N | 1 | 2 | 3 | 4 | 5 | 6 | 
|  |  |  |  | |||
| 96 | (12 | * | ÷ 3) ! | × 4 |  |  | 
| 123 | 123 |  |  |  |  | |
| 130 | 1 | + 2 | + 3 |  + 4 | + 5! |  | 
| 1728 | 123 | * | * |  |  | |
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